3y=y^2-10

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Solution for 3y=y^2-10 equation:


Simplifying
3y = y2 + -10

Reorder the terms:
3y = -10 + y2

Solving
3y = -10 + y2

Solving for variable 'y'.

Reorder the terms:
10 + 3y + -1y2 = -10 + y2 + 10 + -1y2

Reorder the terms:
10 + 3y + -1y2 = -10 + 10 + y2 + -1y2

Combine like terms: -10 + 10 = 0
10 + 3y + -1y2 = 0 + y2 + -1y2
10 + 3y + -1y2 = y2 + -1y2

Combine like terms: y2 + -1y2 = 0
10 + 3y + -1y2 = 0

Factor a trinomial.
(5 + -1y)(2 + y) = 0

Subproblem 1

Set the factor '(5 + -1y)' equal to zero and attempt to solve: Simplifying 5 + -1y = 0 Solving 5 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1y = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1y = 0 + -5 -1y = 0 + -5 Combine like terms: 0 + -5 = -5 -1y = -5 Divide each side by '-1'. y = 5 Simplifying y = 5

Subproblem 2

Set the factor '(2 + y)' equal to zero and attempt to solve: Simplifying 2 + y = 0 Solving 2 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + y = 0 + -2 Combine like terms: 2 + -2 = 0 0 + y = 0 + -2 y = 0 + -2 Combine like terms: 0 + -2 = -2 y = -2 Simplifying y = -2

Solution

y = {5, -2}

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